Question

Consider the equilibrium system described by the chemical reaction below. Determine the concentration of o₂ at equilibrium by writing the equilibrium constant expression and solving it. Complete parts 1-2 before submitting your answer. 2 h₂o(g) ⇌ 2 h₂(g) o₂(g).

Answer 1

The equilibrium constant, Ke, for the given reaction is 2.96.

Step-by-step explanation:

To determine the concentration of O₂ at equilibrium for the given reaction 2 H₂O(g) ⇌ 2 H₂(g) + O₂(g), we need to write the equilibrium constant expression, which is defined as

K = [H₂]^2 [O₂] / [H₂O]^2

To solve for the concentration of O₂, you would need the concentrations of H₂O and H₂ at equilibrium.The equilibrium constant expression for the given reaction is:

Ke = ([SO3]^2) / ([SO2]^2 * [O2])

Given the concentrations at equilibrium, we can substitute the values into the expression to calculate Ke:

Ke = (1.1^2) / (0.9^2 * 0.35) = 2.96

Therefore, the equilibrium constant, Ke, for the reaction is 2.96.