Final answer:
To have 1.00 g of TCE from a 10.0 ppm TCE solution, you need 100,000 mL of the solution, as determined by setting up a proportion based on the definition of ppm.
Step-by-step explanation:
To determine how many milliliters of a 10.0 ppm TCE (trichloroethylene) solution are needed to have 1.00 g of TCE, you can use the definition of ppm (parts per million). The question gives us a concentration of 10.0 ppm as the mass of solute per volume of solution. This means that for every one million parts (by volume) of the solution, there are 10.0 parts (by mass) of TCE.
Since ppm is mass/volume, we can express it as:
- 10.0 ppm = 10.0 mg TCE / 1 L solution
To find how many milliliters are needed for 1.00 gram of TCE, which is 1000 mg (since 1 g = 1000 mg), we set up a proportion:
10.0 mg TCE is to 1,000 mL as 1000 mg TCE is to X mL.
Now we can solve for X:
(10.0 mg TCE / 1000 mL) = (1000 mg TCE / X mL)
X = (1000 mg TCE * 1000 mL) / 10.0 mg TCE
X = 100,000 mL
Therefore, you would need 100,000 mL of the 10 ppm TCE solution to have 1.00 g of TCE.