Final answer:
In molecule (a) there are 4 sigma bonds and 0 pi bonds, in molecule (b) there are 5 sigma bonds and 1 pi bond, and in molecule (c) there are 10 sigma bonds and 3 pi bonds.
Step-by-step explanation:
In molecule (a), there are 4 sigma bonds and 0 pi bonds. Sigma bonds are formed from the end-to-end overlap of orbitals, and pi bonds are formed from the side-by-side overlap of orbitals. Since there are no double or triple bonds in molecule (a), there are no pi bonds present.
In molecule (b), there are 5 sigma bonds and 1 pi bond. The pi bond is formed in the double bond between the two atoms. The sigma bonds are formed by the end-to-end overlap of orbitals.
In molecule (c), there are 10 sigma bonds and 3 pi bonds. The pi bonds are formed in the double and triple bonds between the atoms. The sigma bonds are formed by the end-to-end overlap of orbitals.