Final answer:
The wavelength of visible light with a frequency of 5.347×10^14 Hz is approximately 559 nm. The energy per photon is approximately 3.542×10^-19 J. The color of the light falls within the range of visible light, but the specific color cannot be determined without the exact wavelength.
Step-by-step explanation:
Visible light has a frequency of 5.347×1014 Hz. To determine its wavelength, we can use the formula v = λf, where v is the speed of light (approximately 3×108 m/s), λ is the wavelength, and f is the frequency. Rearranging the formula, we find that the wavelength is equal to the speed of light divided by the frequency.
Using the given frequency of 5.347×1014 Hz, the wavelength is approximately 5.599×10-7 m or 559 nm.
To determine the energy per photon, we can use the formula E = hf, where E is the energy, h is Planck's constant (approximately 6.626×10-34 J·s), and f is the frequency. Rearranging the formula, we find that the energy is equal to Planck's constant multiplied by the frequency.
Using the given frequency of 5.347×1014 Hz, the energy per photon is approximately 3.542×10-19 J.
The color of visible light depends on its wavelength. In general, shorter wavelengths correspond to blue or violet light, while longer wavelengths correspond to red light. The wavelength of 5.599×10-7 m falls within the range of visible light, so the color would be somewhere between blue and red. However, without knowing the exact wavelength, it is difficult to determine the specific color.