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We have 2 electromagnetic waves. wave 1 has a wavelength 3 times greater than wave 2. if wave 2 has a wavelength = 618 nm, what then would be the ratio ?

User Dharini S
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Final answer:

The ratio of the wavelengths of two electromagnetic waves, where one wavelength is 3 times greater than the other with a reference wavelength of 618 nm, is 3:1.

Step-by-step explanation:

Wave 1 has a wavelength that is 3 times greater than wave 2. Given that the wavelength of wave 2 is 618 nm, the wavelength of wave 1 would be 3 * 618 nm, which equals 1854 nm. The ratio of the wavelengths of wave 1 to wave 2 is therefore 1854 nm to 618 nm, simplifying to a ratio of 3:1.

According to Equation 3.2.4, the speed of an electromagnetic wave (c) is the product of its frequency (f) and wavelength (λ), which for electromagnetic radiation is 2.998 × 108 m/s. This means that if the wavelength is increased by a factor of 3, the frequency is decreased by a factor of 3, since the speed of light is constant.

User La
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