Final answer:
To find the magnitude of the particle's acceleration in the given circular motion, differentiate the motion equations twice with respect to time and calculate the magnitude of the acceleration vector using the x and y components.
Step-by-step explanation:
The particle's motion is given by the equations x = a cos(ωt) and y = a sin(ωt), where a = 1.5 meters and ω = 2.0 radians per second. To find the magnitude of the particle's acceleration, we can differentiate the equations twice with respect to time. The acceleration vector can be found using the equations:
ax = -aω² cos(ωt), ay = -aω² sin(ωt)
The magnitude of the particle's acceleration can be found by taking the square root of the sum of the squares of the x and y components of the acceleration: a = √(ax² + ay²)
Plugging in the values a = 1.5, ω = 2.0, and t = 0, we can calculate the magnitude of the particle's acceleration.