Question

A mixture of krypton and oxygen gas is expanded from a volume of 10.0 L to a volume of 58.0 L, while the pressure is held constant at 44.0 atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Answer 1

The work done on a gas mixture expanded from 10.0 L to 58.0 L at a constant pressure of 44.0 atm is -213,235.2 J.

Step-by-step explanation:

To calculate the work done on a gas mixture during an expansion, we use the formula W = -P∆V, where W is the work done on the gas, P is the constant pressure, and ∆V is the change in volume. In this case, the volume changes from 10.0 L to 58.0 L with a constant pressure of 44.0 atm. We must also convert the work from liter atmospheres to joules by using 1 L·atm = 101.32 J.

The change in volume (∆V) is 58.0 L - 10.0 L = 48.0 L. Calculating the work using the given formula: W = -(44.0 atm)(48.0 L).

Now we convert the result to joules: W = -(44.0 atm)(48.0 L)(101.32 J/L·atm), which yields W = -213,235.2 J. The negative sign indicates that the work is done on the gas mixture, not by the gas mixture.