Question

A heavy swing door has a mass of m = 3,000 kg, a width w = 1.5 m, and a height h = 2.7 m. The moment of inertia of this door about the vertical axis of rotation is given by i = 1/12 mw^2. Calculate the moment of inertia

Answer 1

The moment of inertia of the heavy swing door is 1875 kg · m².

Step-by-step explanation:

The moment of inertia of a heavy swing door can be calculated using the formula i = 1/12 mw^2, where m is the mass of the door and w is the width. In this case, the mass of the door is 3000 kg and the width is 1.5 m. Substituting these values into the formula gives:

i = (1/12) * 3000 kg * (1.5 m)^2 = 1875 kg · m²

So, the moment of inertia of the door about the vertical axis of rotation is 1875 kg · m².