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A microorganism swimming through water at a speed of 150 μm/sμm/s suddenly stops swimming. its speed drops to 75 μm/sμm/s in 1.5 msms. what is the total distance in μm it travels while stopping?

User Vitrilo
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1 Answer

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Final answer:

To calculate the distance traveled by a microorganism while decelerating, we use motion equations with given initial and final speeds, time, and derived acceleration. After computing the deceleration, the distance is found to be 112.5 μm.

Step-by-step explanation:

To calculate the total distance traveled by a microorganism while stopping, we can use the equations of motion under constant acceleration (in this case, negative acceleration or deceleration). The initial speed (vi) of the microorganism is 150 μm/s. It slows down to a final speed (vf) of 75 μm/s in a given time (t) of 1.5 ms (or 1.5 × 10−6 s).

The deceleration (a) can be found using the formula: a = (vf - vi) / t.

After calculating the deceleration, we can find the distance (d) using the formula: d = vi × t + 0.5 × a × t2.

Lets plug in the values:

  • vi = 150 μm/s
  • vf = 75 μm/s
  • t = 1.5 ms = 1.5 × 10−3 s

First, we find the deceleration:

a = (75 μm/s - 150 μm/s) / (1.5 × 10−3 s) = -50,000 μm/s2

Now we calculate the distance:

d = (150 μm/s × 1.5 × 10−3 s) + 0.5 × (-50,000 μm/s2) × (1.5 × 10−3 s)2 = 112.5 μm.

User Thoku
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