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The half-life of a first-order reaction is 13 min. if the initial concentration of reactant is 0.085 m, then how many minutes would it take for the reactant to decrease to 0.021 m.

(a) 8.2
(b) 13
(c) 18.2
(d) 26
(e) 22.4

1 Answer

1 vote

Final answer:

To find the time required for the reactant concentration to decrease from 0.085 M to 0.021 M in a first-order reaction with a 13-minute half-life, we observe that after two half-lives, the concentration is approximately 0.021 M, indicating that the time needed is just under 26 minutes.

Step-by-step explanation:

The question is about calculating the time it will take for the concentration of a reactant to decrease from 0.085 M to 0.021 M in a first-order reaction with a half-life of 13 minutes. By using the concept of half-lives, we can determine that each half-life cuts the reactant concentration in half. To go from 0.085 M to 0.021 M, we need to determine how many half-lives have passed:

  • After one half-life (13 min), the concentration goes from 0.085 M to 0.0425 M.
  • After another half-life (total of 26 min), it would go from 0.0425 M to 0.02125 M.

Since the desired concentration is 0.021 M, which is slightly less than the concentration after two half-lives (0.02125 M), the total time required will be slightly less than 26 minutes. Thus, the correct answer is (d) 26 minutes, recognizing the closest approximation provided.

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