165k views
1 vote
The equation of a line is written in standard form: 4x-8y=12 what is the slope of this line?

User Dly
by
8.1k points

2 Answers

4 votes

Answer: y=-1/2x+3/2

Step-by-step explanation:

4x-8y=12

Move the 4x to the other side by subtracting.

8y=-4x+12

Divide 8 to all terms.

y=-4/8x+12/8

Simplify.

y=-1/2x+3/2

User DazManCat
by
8.5k points
4 votes

Final answer:

The slope of the line represented by the equation 4x - 8y = 12 is 1/2, found by rewriting the equation in slope-intercept form (y = mx + b) and identifying the coefficient of x as the slope.

Step-by-step explanation:

The equation of a line in standard form is given as 4x - 8y = 12, and you want to find the slope of this line. To find the slope from the standard form, the equation needs to be re-written in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. Here's how to do it step-by-step:

  • First, move the x term to the other side of the equation: -8y = -4x + 12.
  • Next, divide every term by -8, the coefficient of y, to isolate y: y = ½x - ÷.

Now, the equation is in slope-intercept form, and the coefficient of x (1/2) is the slope. Therefore, the slope of the line is 1/2. This means that the line rises 1 unit vertically for every 2 units it moves horizontally.

User Matt Pollock
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories