The reason for this is that the volume of a pyramid is directly proportional to the cube of its linear dimensions. When the side lengths of the base are reduced by one inch each, the new volume is calculated by using the reduced dimensions in the volume formula. The correct answer is b. Original volume: 417.7 cubic inches; reduced volume: 213.3 cubic inches.
In a pyramid, the volume (V) is given by the formula . The original pyramid has a base with side length inches, so the original base area square inches. The height is 10 inches. Therefore, the original volume cubic inches.
For the reduced size pyramid, the new base side length is inches. The reduced base area is square inches. The height (\(h\)) remains 10 inches. Therefore, the reduced volume is cubic inches.
The volume ratio of the original to the reduced pyramid is . As this ratio is less than 1, the reduced volume is smaller than the original volume. Among the options, the only one that satisfies this condition is option b.
The correct answer is b. Original volume: 417.7 cubic inches; reduced volume: 213.3 cubic inches.
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