Final answer:
The mass of ice per second that melts can be determined using the formula Q = k * A * (T1-T2) / L, where Q is the rate of heat transfer, k is the thermal conductivity of copper, A is the cross-sectional area of the rod, T1 is the temperature of boiling water, T2 is the temperature of ice water, and L is the length of the rod.
Step-by-step explanation:
The mass of ice per second that melts can be determined using the formula for heat transfer through conduction. The rate of heat transfer (Q) can be calculated using the equation Q = k * A * (T1-T2) / L, where k is the thermal conductivity of copper, A is the cross-sectional area of the rod, T1 is the temperature of boiling water, T2 is the temperature of ice water, and L is the length of the rod. In this case, we assume no heat is lost through the side surface of the rod.
Let's plug in the given values:
- Length of rod (L): 1.7m
- Cross-sectional area of rod (A): 4.1x10^-4 m^2
- Temperature of boiling water (T1): 100°C
- Temperature of ice water (T2): 0°C
- Thermal conductivity of copper (k): 401 W/mK
Substituting these values into the equation, we have:
Q = (401 W/mK) * (4.1x10^-4 m^2) * (100°C-0°C) / (1.7m)
Simplifying this expression gives us the rate of heat transfer, which is numerically equal to the mass of ice per second that melts.