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A clerk moves a box of cans down an aisle by pulling on a strap attached to the box. the clerk pulls with a force of 185.0 n at an angle of 25.0 degrees with the horizonal. the bos has a mass of 35.0 kg and the coefficeint of kinetic friction between the box and floor is 0.450 find the acceleration of the box

User TarHalda
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Final answer:

To find the acceleration of the box, calculate the net force acting on it and divide it by the mass of the box. Find the horizontal component of the applied force using Fx = F * cos(theta), and determine the frictional force using Ffriction = friction coefficient * normal force. Subtract the frictional force from the horizontal component of the applied force to find the net force. Finally, divide the net force by the mass of the box to find the acceleration.

Step-by-step explanation:

To find the acceleration of the box, we need to calculate the net force acting on it and divide it by the mass of the box.

The clerk is pulling the box with a force of 185.0 N at an angle of 25.0 degrees with the horizontal. The horizontal component of this force can be found using the equation Fx = F * cos(theta). Therefore, Fx = 185.0 N * cos(25.0 degrees).

The frictional force acting on the box can be found using the equation Ffriction = friction coefficient * normal force. The normal force is the weight of the box, which can be found using the equation Weight = mass * g, where g is the acceleration due to gravity. The frictional force can then be used to calculate the net force acting on the box by subtracting it from the horizontal component of the applied force.

Finally, the acceleration of the box can be found using the equation Fnet = mass * acceleration, rearranging this equation for acceleration gives acceleration = Fnet / mass.

Substituting the values into the equations and calculating will provide the acceleration of the box.

User Gustyn
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