Question

In some areas, the temperature in a pool is not always warm. On the first day the pool was open, the temperature of the water was 68 degrees. After 10 days of sun (and a pool heater), the temperature had increased to 90 degrees. Assume the temperature of the water increased linearly. What is the slope in this situation? Do not include units in your answer.

a. 2.2
b. 2.4
c. 2.8
d. 3.0

Answer 1

The slope of the temperature change in the pool is calculated to be 2.2 degrees per day.

Step-by-step explanation:

In this situation, the temperature of the pool water increased linearly from 68 degrees to 90 degrees over a 10-day period. To find the slope, we need to determine the change in temperature per day. We can use the formula:

Slope = (change in temperature)/(change in time)

Therefore, the slope in this situation is 2.2.The student has asked to calculate the slope of the temperature change in the pool over a period of 10 days. In mathematics, the slope is calculated as the change in y divided by the change in x, in this case, the change in temperature divided by the change in time. Since the temperature of the pool water increased from 68 degrees to 90 degrees over 10 days, the change in temperature (ΔT) is 90 - 68 = 22 degrees. The change in time (Δt) is 10 days. Therefore, the slope (m) = ΔT / Δt = 22°/10 days = 2.2°/day.