Final answer:
After 10 seconds of constant acceleration at 0.6 m/s², a bicyclist's initial speed of 5 m/s increases to a final speed of 11 m/s. This acceleration, calculated using the formula \(v = u + at\), results in a smooth transition, showcasing the impact of a consistent rate on velocity.
Step-by-step explanation:
When a bicyclist who is traveling at an initial speed of 5 m/s accelerates at a constant rate of 0.6 m/s² for 10 s, we can calculate the final speed using the formula for constant acceleration: v = u + at. Where: v is the final velocity, u is the initial velocity (5 m/s), a is the acceleration (0.6 m/s²), and t is the time (10 s). Plugging in the values: v = 5 m/s + (0.6 m/s² × 10 s), v = 5 m/s + 6 m/s, v = 11 m/s. Therefore, the final speed of the bicycle at the end of the 10 seconds is 11 m/s.