Question

In 2014, the rosetta space probe reached the comet churyumov-gerasimenko. if a rock were dropped from a height of 0.60 m above the comet's surface, how long would it take to hit the surface?

a. 0.35 seconds
b. 0.42 seconds
c. 0.48 seconds
d. 0.55 seconds

Answer 1

The rock would take approximately 0.35 seconds to hit the comet's surface when dropped from a height of 0.60 m.

Step-by-step explanation:

To calculate the time it takes for a rock dropped from a height of 0.60 m above the comet's surface to hit the surface, we can use the equation for the time of free fall:

t = sqrt(2h/g)

Where:

• t is the time of free fall
• h is the height from which the object is dropped (in meters)
• g is the acceleration due to gravity (approximately 9.8 m/s² on Earth)

Plugging in the values, we have:

t = sqrt(2 * 0.60 / 9.8) = sqrt(0.1224) = 0.35 seconds

Therefore, the rock would take approximately 0.35 seconds to hit the surface.