Final answer:
To find a 95% confidence interval and determine if the SAT scores between the two groups are significantly different, we can use the formula for the confidence interval. Plugging in the given values and calculating, the confidence interval is (82.73, 107.27). Since the confidence interval does not include 51.35, we can conclude that the SAT scores between the two groups are significantly different. The correct option is c. μ1 - μ2 ≠ 51.35.
Step-by-step explanation:
To find a 95% confidence interval and determine if the SAT scores between the two groups are significantly different, we can use the formula for the confidence interval:
CI = (X1 - X2) ± Z * √((σ1^2/n1) + (σ2^2/n2))
Where:
- X1 and X2 are the sample means
- σ1 and σ2 are the population standard deviations
- n1 and n2 are the sample sizes
- Z is the critical value
Plugging in the given values:
X1 = 1225, X2 = 1130, σ1 = 95, σ2 = 103, n1 = n2 = 500
The critical value for a 95% confidence interval is approximately 1.96.
Calculating the confidence interval:
CI = (1225 - 1130) ± 1.96 * √((95^2/500) + (103^2/500))
CI = 95 ± 1.96 * √(9025/500 + 10609/500)
CI = 95 ± 1.96 * √(18.05 + 21.218)
CI = 95 ± 1.96 * √(39.268)
CI = 95 ± 1.96 * 6.266
CI = 95 ± 12.27
CI = (82.73, 107.27)
Since the confidence interval does not include 51.35, we can conclude that the SAT scores between the two groups are significantly different. Therefore, the correct option is c. μ1 - μ2 ≠ 51.35.