Question

If you can have him stand up and take the blood pressure at his calf, which is 94.5cm below his heart, what would be the magnitude p of the difference between this measurement of blood pressure and a normal blood-pressure measurement? The density of the blood is 1060 kg/m³.

Options:
a. p=94.5×1060
b. p= 106094.5
c. p=94.5+1060
d. p=94.5−1060

Answer 1

The magnitude of the difference between the blood pressure measurement at the calf and a normal blood pressure measurement would be 981,540 N/m².

Step-by-step explanation:

To calculate the pressure at the calf, we can use the equation P = hpg, where P is the pressure, h is the height (94.5 cm), p is the density of the blood (1060 kg/m³), and g is the acceleration due to gravity (9.8 m/s²).

P = (94.5 cm)(1060 kg/m³)(9.8 m/s²) = 981,540 kg/(m·s²) = 981,540 N/m².

Therefore, the magnitude of the difference between the pressure at the calf and a normal blood-pressure measurement would be 981,540 N/m².