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If f(x) = x^4-5x^3-5, then what is the remainder when f(x) is divided by x-6?

User Matuku
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1 Answer

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Final answer:

Using the Remainder Theorem, the remainder when f(x) = x^4 - 5x^3 - 5 is divided by x - 6 is calculated by plugging 6 into the function, yielding a remainder of 211.

Step-by-step explanation:

To find the remainder when the function f(x) = x^4 - 5x^3 - 5 is divided by x - 6, we can use the Remainder Theorem. According to the theorem, if a polynomial f(x) is divided by x - a, the remainder is f(a). Therefore, to find the remainder of f(x) divided by x - 6, we need to calculate f(6).

Substituting 6 into the function, we get:

f(6) = 6^4 - 5(6)^3 - 5

f(6) = 1296 - 5(216) - 5

f(6) = 1296 - 1080 - 5

f(6) = 216 - 5

f(6) = 211

Therefore, the remainder when f(x) is divided by x - 6 is 211.

User Oyo
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