Question

What is the value of e, the margin of error, for a confidence level of 0.95, a sample size of 10, and a difference between the means of 3.7?

a) 1.645
b) 1.96
c) 2.58
d) 3.17

Answer 1

The value of e, the margin of error, for a 95% confidence level, a sample size of 10, and a difference between the means of 3.7 is 2.58.

Step-by-step explanation:

The value of e, the margin of error, for a 95% confidence level, a sample size of 10, and a difference between the means of 3.7 can be calculated using the formula:

e = Z * (sigma/√n)

Where:

• Z is the z-value corresponding to the desired confidence level (in this case, 1.96 for a 95% confidence level)
• sigma is the standard deviation of the sample (difference between the means)
• n is the sample size

Plugging in the values:

e = 1.96 * (3.7/√10) = 2.58

Therefore, the value of e, the margin of error, is 2.58. The correct answer is c) 2.58.