Question

He random variable X has the probability distribution table shown below.

x 6 8 10 12 14
P(X = x) 0.2 0.2 a a 0.2
(a)
Assuming
P(X = 10) = P(X = 12),
find each of the missing value

Answer 1

To find the missing values in the probability distribution table, we solve for the value that makes the sum of probabilities equal to 1, using the fact that P(X = 10) = P(X = 12). Therefore, the missing values are a = 0.2.

Step-by-step explanation:

Answer:

To find the missing values, we need to use the fact that P(X = 10) = P(X = 12).

Given that P(X = 10) = 0.2, we can solve for the missing value.

P(X = 10) + P(X = 12) + a + a + 0.2 = 1.

0.2 + 0.2 + a + a + 0.2 = 1.

0.4 + 2a + 0.2 = 1.

2a = 1 - 0.4 - 0.2.

2a = 0.4.

a = 0.2.

Therefore, the missing values are a = 0.2.