110k views
1 vote
If a current is 2.7 A, how many turns per centimeter must be wound on a solenoid to produce a magnetic field of 1.1 × 10⁻³ T within it

a) 0.08 turns/cm
b) 0.11 turns/cm
c) 0.14 turns/cm
d) 0.17 turns/cm

User AAndrei
by
7.6k points

1 Answer

4 votes

Final answer:

In order to produce a magnetic field of 1.1 × 10⁻³ T within a solenoid with a current of 2.7 A, approximately 0.14 turns per centimeter must be wound.

The answer is option ⇒c) 0.14 turns/cm

Step-by-step explanation:

To calculate the number of turns per centimeter required to produce a magnetic field of 1.1 × 10⁻³ T within a solenoid with a current of 2.7 A, we can use the formula:

B = μ₀ * n * I

Where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T*m/A), n is the number of turns per centimeter, and I is the current. Rearranging the formula, we get:

n = B / (μ₀ * I)

Plugging in the given values, we have:

n = (1.1 × 10⁻³ T) / (4π × 10⁻⁷ T*m/A * 2.7 A)

Simplifying this expression, we get n ≈ 0.14 turns/cm.

Therefore, the correct answer is c) 0.14 turns/cm.

User Ccocker
by
7.8k points