Question

Ian, jim, sergio, dawn, katrina, eduardo, sarah, and simone have all been invited to a dinner party. they arrive randomly and each person arrives at a different how many ways can simone arrive first and jim ​last

a) 1440
b) 5040
c) 720
d) 40320

Answer 1

To find the number of ways Simone can be first and Jim last to arrive at the party, we calculate the factorial of the remaining six guests, which is 720 ways.

Step-by-step explanation:

The question pertains to the number of ways Simone can arrive first and Jim last at a dinner party with a total of eight invitees. We need to calculate the permutations of the remaining six guests, since Simone and Jim's positions are fixed.

Since there are 6 guests who can arrive in any order between Simone and Jim, we have 6! (6 factorial) ways of arranging them. The factorial of a number n, denoted as n!, is the product of all positive integers up to n. So, 6! = 6 × 5 × 4 × 3 × 2 × 1 = 720.

Therefore, there are 720 different ways for the guests to arrive with Simone first and Jim last.