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If a pair of Magdeburg hemispheres have a radius of 15 cm, and the vacuum pump reduces the interior pressure to 0.08 atm, what force must be applied to pull the hemispheres apart

a) 141.3 N
b) 188.4 N
c) 235.5 N
d) 282.6 N

User Zlo
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1 Answer

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Final answer:

The force required to pull the Magdeburg hemispheres apart is approximately 648 N.

Step-by-step explanation:

To calculate the force required to pull the Magdeburg hemispheres apart, we can use the formula F = P x A, where F is the force, P is the pressure, and A is the cross-sectional area. The pressure can be calculated by subtracting the interior pressure from atmospheric pressure. The cross-sectional area can be calculated using the formula A = πr^2, where r is the radius of the hemispheres. Plugging in the given values (radius = 15 cm and pressure = 0.08 atm), we can calculate the force:

F = (1 atm - 0.08 atm) x π(15 cm)^2

F ≈ 0.92 atm x π(15 cm)^2

F ≈ 0.92 x 15^2 x 3.14 N

F ≈ 0.92 x 225 x 3.14 N

F ≈ 648 N

Therefore, the force required to pull the hemispheres apart is approximately 648 N. None of the given options (a, b, c, d) match this result, so the correct answer is not provided.

User Alan Szlosek
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