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If a bowling ball with a momentum of 16 kg * m/s and rolls into a pillow and stops in 0.5 seconds, what is the average force the ball exerts on the pillow

a) 8 N
b) 16 N
c) 24 N
d) 32 N

User JaredL
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1 Answer

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Final answer:

The average force exerted by the bowling ball on the pillow is 32 N.

Step-by-step explanation:

To find the average force exerted by the bowling ball on the pillow, we can use the equation: average force = change in momentum / time. The bowling ball's initial momentum is 16 kg * m/s and it stops in 0.5 seconds. Therefore, the change in momentum is 16 kg * m/s - 0 kg * m/s = 16 kg * m/s. The average force exerted by the bowling ball on the pillow is then: average force = 16 kg * m/s / 0.5 s = 32 N.

User GavinWoods
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