Final answer:
One can create 210 distinct three-digit numbers from the set {1, 2, 3, 4, 5, 6, 7} without repeating any digits by multiplying the choices for each digit place: 7 choices for the first, 6 for the second, and 5 for the third.
Step-by-step explanation:
To calculate how many three-digit numbers can be formed using the numbers {1, 2, 3, 4, 5, 6, 7} without repetition, we consider each digit position independently.
Now, we multiply the number of choices for each digit together to find the total number of three-digit numbers we can create: 7 × 6 × 5 = 210
Therefore, the correct answer is c. 210.