Question

How many moles of oxygen (O2) are contained in a 5.8 L cylinder that has a pressure of 132 atm and a temperature of 14°C?

a. 51
b. 1.63
c. 2.75
d. 3.21

Answer 1

To find the number of moles of oxygen (O2) in the cylinder, we can use the ideal gas law equation: PV = nRT. The calculation yields approximately b)1.63 moles.

Step-by-step explanation:

The subject of this question is Chemistry, and it is appropriate for High School grade level.

To calculate the number of moles of oxygen (O₂) in a cylinder, the ideal gas law can be used: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

To find the number of moles of oxygen (O2) in the cylinder, we can use the ideal gas law equation: PV = nRT. Rearranging the equation, we have n = PV / RT.

Plugging in the given values, we get n = (132 atm)(5.8 L) / (0.0821 atm L / (mol K))(14 + 273) K.

Solving this equation gives us approximately 1.63 moles. Therefore, the answer is b. 1.63.