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How many moles of nacl are present in each solution?
(a) 2.5 l of a 1.5 m nacl solution

User Oded Niv
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Final answer:

There are 3.75 moles of NaCl in 2.5 liters of a 1.5 M NaCl solution. To determine the number of moles of NaCl in the solution, multiply the molarity by the volume of the solution.

Step-by-step explanation:

The calculation to determine the number of moles of NaCl present in a solution can be done using the formula:

Moles = Molarity x Volume

In this case, the molarity (M) is given as 1.5 moles per liter (1.5 M), and the volume is 2.5 liters. Plugging these values into the formula:

Moles = 1.5 M x 2.5 L = 3.75 moles of NaCl

This result indicates the amount of NaCl molecules present in the solution, considering the concentration (molarity) and the volume. It's essential to use consistent units and remember that moles represent a specific quantity of substance, providing a standardized measure for chemical calculations.

In simple terms, if you have a more concentrated solution (higher molarity) or a larger volume, you'll have more moles of solute. In this example, the higher molarity contributes to the relatively large number of moles of NaCl in the given volume.

User Csfb
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