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a solid concrete block weighs 169 n and is resting on the ground. its dimensions are 0.4m * 0.2m * 0.1 m. a number of identical blocks are stacked on top of this one. what is the smallest number of whole blocks (including the one on the ground) that can be stacked so that their weight creates a pressure of at least two atmospheres on the ground beneath the first block?

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Final answer:

To create a pressure of two atmospheres, we need to stack 96 concrete blocks on top of the first one, as each block weighs 169 N and the area they cover is 0.08 m².

Step-by-step explanation:

To calculate the minimum number of concrete blocks needed to create a pressure of at least two atmospheres on the ground beneath the first block, we first need to understand that one atmosphere of pressure is 1.01 × 105 N/m². Therefore, a pressure of two atmospheres would be 2.02 × 105 N/m². The area over which the blocks exert pressure on the ground is 0.4m * 0.2m = 0.08 m². Dividing the required pressure by this area gives us the total force needed to create this pressure.

To calculate the force needed: 2.02 × 105 N/m² × 0.08 m² = 16160 N. Given that one block has a weight of 169 N, we need to stack enough blocks so their total weight equals or exceeds 16160 N. Therefore, the number of blocks needed is 16160 N divided by 169 N per block, which gives approximately 95.6 blocks. Since we cannot have a fraction of a block, we'd need 96 blocks in total (including the one on the ground) to create the desired pressure.

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