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If 1.2L of N2 reacts with 3.6L of H2, what volume of NH3 is produced if all the N2 and H2 are consumed?

User DysaniazzZ
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Final answer:

In a reaction of 1.2L N₂ with 3.6L H₂ adhering to Avogadro's law, twice the volume of N₂, which is 2.4L of NH₃, is produced.

Step-by-step explanation:

The question at hand involves a chemical reaction where nitrogen gas (N₂) reacts with hydrogen gas (H₂) to produce ammonia gas (NH₃). According to Avogadro's law, equal volumes of gasses at the same temperature and pressure contain equal numbers of molecules.

Therefore, when we look at the balanced equation N₂ (g) + 3 H₂ (g) → 2 NH₃ (g), we know that one volume of N₂ reacts with three volumes of H₂ to produce two volumes of NH₃. Given that 1.2L of N₂ reacts with 3.6L of H₂, the expected volume of NH₃ produced would be twice the volume of N₂, resulting in 2.4L of NH₃.

User Bobby C
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