Final answer:
To calculate the enthalpy change per mole of zinc for the reaction Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g), convert the mass of zinc to moles, then divide the heat produced by the number of moles of Zn. The enthalpy change is -153.17 kJ/mol.
Step-by-step explanation:
The question asks for the calculation of the heat change, or enthalpy change (ΔH°rxn), for the reaction of zinc with hydrochloric acid. According to the information provided, when 1.34 g of zinc (Zn) reacts with hydrochloric acid (HCl), 3.14 kJ of heat are produced. The reaction is Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g).
To find the enthalpy change per mole of zinc, we first convert the mass of zinc to moles using its molar mass (65.38 g/mol for Zn):
Moles of Zn = mass of Zn / molar mass of ZnMoles of Zn = 1.34 g / 65.38 g/mol = 0.0205 mol
Now, we can calculate the enthalpy change per mole of Zn:
ΔH°rxn = Heat produced / Moles of ZnΔH°rxn = 3.14 kJ / 0.0205 mol = 153.17 kJ/mol
Therefore, for each mole of zinc reacting, the enthalpy change is -153.17 kJ/mol (negative sign indicates it's an exothermic reaction).