Final answer:
Using Einstein's equation E = mc² and the given power output, the mass of the star decreases by 3.64 kg per second due to its energy output.
Step-by-step explanation:
To determine the decrease in mass of a star per second based on its power output using Einstein's equation E = mc², we will use the given power output of 3.28 × 10²¶ W (watts) as the energy E. According to Einstein's equation, energy E is equal to the mass m times the speed of light c squared. The speed of light c is approximately 3.00 × 10¸ m/s. To find the mass, we rearrange the equation to m = E/c².
Plugging in the values, we have m = (3.28 × 10²¶ W) / (3.00 × 10¸ m/s)². Calculating this gives us the mass decrease per second. Performing the calculation:
m = (3.28 × 10²¶ J/s) / (9.00 × 10±¶ m²/s²) = 3.64 × 10¹ kg/s.
Therefore, the star's mass decreases by 3.64 kg each second due to its energy output.