Final answer:
To obtain the overall reaction NH₃(g) + BH₃(g) + O₂(g), we need to combine reactions a, b, and c. By combining reaction b: N₂(g) + 3H₂(g) → 2NH₃(g), reaction a: 2H₂O(g) → 2H₂(g) + O₂(g), and reaction c: 2Br(g) + Br₂(g), we can write the overall reaction as 2NH₃(g) + 2BH₃(g) + O₂(g).
Step-by-step explanation:
To obtain the overall reaction NH₃(g) + BH₃(g) + O₂(g), we need to combine reactions a, b, and c.
Starting with reaction b: N₂(g) + 3H₂(g) → 2NH₃(g), we can see that 1 mole of NH₃ is formed for every 1 mole of N₂ consumed.
Next, we can combine reaction a: 2H₂O(g) → 2H₂(g) + O₂(g), which shows that 2 moles of H₂ are formed for every 1 mole of O₂ consumed.
Finally, we can combine reaction c: 2Br(g) + Br₂(g), which shows that 2 moles of Br are formed for every 1 mole of Br₂ consumed.
By combining these three reactions, we can write the overall reaction as: 2NH₃(g) + 2BH₃(g) + O₂(g).