Final answer:
The number of liters of CO₂ produced at STP if the cylinder contains 816 g of propane is 15 L. we first find the moles of propane and then use the stoichiometry from the balanced combustion equation. So option 2 is correct..
Step-by-step explanation:
To determine the number of liters of CO₂ produced at STP if the cylinder contains 816 g of propane, we can use stoichiometry. The balanced chemical equation for the combustion of propane is:
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g)
From the equation, we can see that for every 1 mol of propane, 3 mol of CO₂ is produced. We can convert the mass of propane to moles using its molar mass, which is 44.1 g/mol. So, 816 g of propane is equal to:
(816 g) / (44.1 g/mol) = 18.5 mol of propan
Therefore, the number of liters of CO₂ produced at STP is:
(18.5 mol propane) x (3 mol CO₂ / 1 mol propane) x (22.4 L/mol) = 1242 L of CO₂.