Final answer:
To calculate the volume of 0.25M NaOH needed to react with acetic acid in vinegar, the concentration of acetic acid is required. With that, moles of acetic acid can be calculated, and then using stoichiometry, the volume of NaOH is obtained. Without acetic acid's concentration, the calculation cannot be completed.
Step-by-step explanation:
To determine the volume of 0.25M NaOH solution needed to completely react with the acetic acid in the 8.3 mL vinegar, we must consider the concentration of acetic acid in vinegar, which is not provided in the question. However, assuming we have the concentration of acetic acid, we can compute the moles of acetic acid in the vinegar using its volume.
Once the moles of acetic acid are known, we use the stoichiometry of the neutralization reaction (which is typically 1:1 for acetic acid and NaOH) to find the moles of NaOH needed. Then, we can calculate the volume required of the NaOH solution using its molarity. Without the concentration of acetic acid, it's impossible to calculate the exact volume of NaOH solution needed.