205k views
2 votes
One number is 6 more than another number. their sum is 40. Find the two numbers.

a. 17 and 22
b. 12 and 23
c. 17 and 23
d. 17 and 24

2 Answers

3 votes

Answer:

b. 17 and 23

Step-by-step explanation:

40=x+(x+6)

40=2x+6

34=2x

x=17

x+6=23

User Peter Saxton
by
9.1k points
4 votes

Final answer:

By setting up an algebraic equation based on the given conditions, we find that the two numbers in question are 17 and 23. This is determined by solving the equation 2x + 6 = 40, where x represents the smaller number.

Step-by-step explanation:

The problem presented is a basic algebra question involving two unknown numbers with given conditions: one number is 6 more than the other, and their sum is 40. Let's define the smaller number as x. According to the problem, the other number would be x + 6.

The sum of these numbers is given as 40, so we can set up the following equation:

x + (x + 6) = 40

Combining the x values gives us:

2x + 6 = 40

Subtracting 6 from both sides gives:

2x = 34

Dividing both sides by 2 gives:

x = 17

Therefore, the smaller number is 17. To find the larger number, we add 6 to 17:

17 + 6 = 23

Conclusively, the two numbers are 17 and 23, which means the correct answer is option (c).

User Georgii Ivankin
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories