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2 votes
One number is 6 more than another number. their sum is 40. Find the two numbers.

a. 17 and 22
b. 12 and 23
c. 17 and 23
d. 17 and 24

2 Answers

3 votes

Answer:

b. 17 and 23

Step-by-step explanation:

40=x+(x+6)

40=2x+6

34=2x

x=17

x+6=23

User Peter Saxton
by
8.5k points
4 votes

Final answer:

By setting up an algebraic equation based on the given conditions, we find that the two numbers in question are 17 and 23. This is determined by solving the equation 2x + 6 = 40, where x represents the smaller number.

Step-by-step explanation:

The problem presented is a basic algebra question involving two unknown numbers with given conditions: one number is 6 more than the other, and their sum is 40. Let's define the smaller number as x. According to the problem, the other number would be x + 6.

The sum of these numbers is given as 40, so we can set up the following equation:

x + (x + 6) = 40

Combining the x values gives us:

2x + 6 = 40

Subtracting 6 from both sides gives:

2x = 34

Dividing both sides by 2 gives:

x = 17

Therefore, the smaller number is 17. To find the larger number, we add 6 to 17:

17 + 6 = 23

Conclusively, the two numbers are 17 and 23, which means the correct answer is option (c).

User Georgii Ivankin
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8.7k points