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How many milliliters of 0.200 m NaOH solution are needed to react with 34.0 mL of a 0.390 m NiCl2 solution?

a. 90.0
b. 75.2
c. 102.5
d. 45.8

User Rraphael
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1 Answer

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Final answer:

To determine the amount of NaOH solution needed to react with 34.0 mL of a 0.390 m NiCl2 solution, we can use the equation moles of NiCl2 = moles of NaOH. First, calculate the moles of NiCl2 using the given molarity and volume. Then, find the moles of NaOH using the mole ratio. Finally, divide the moles of NaOH by the molarity of NaOH to find the volume of NaOH solution needed.

Step-by-step explanation:

To determine the amount of NaOH solution needed, we can use the equation:

moles of NiCl2 = moles of NaOH

First, calculate the moles of NiCl2:

moles of NiCl2 = Molarity of NiCl2 x volume of NiCl2 solution = 0.390 mol/L x 0.0340 L = 0.0133 mol

Since the ratio of moles of NaOH to moles of NiCl2 is 2:1, we can find the moles of NaOH:

moles of NaOH = 2 x moles of NiCl2 = 2 x 0.0133 mol = 0.0266 mol

Finally, we can find the volume of NaOH solution needed:

volume of NaOH solution = moles of NaOH / Molarity of NaOH = 0.0266 mol / 0.200 mol/L = 0.133 L = 133 mL

Therefore, the answer is 133 mL (option c).

User Wizzardz
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