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Calculate the enthalpy of the reaction below (∆hrxn, in kj) using the bond energies provided. n₂(g) 2 h₂(g) → n₂h₄(g)

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Final answer:

To calculate the enthalpy of the reaction, you can use the bond energies provided. Identify the bonds present in the reactants and products and use the table of bond energies to find the bond energies. Sum up the bond energies of the reactants and subtract the bond energies of the products to calculate the enthalpy change (∆Hrxn).

Step-by-step explanation:

To calculate the enthalpy of the reaction, you can use the bond energies provided. The bond energies are given in kJ/mol and represent the energy required to break one mole of a specific bond. In the reaction n₂(g) + 2 h₂(g) → n₂h₄(g), you can calculate the total enthalpy change (∆Hrxn) by summing up the bond energies of the reactants and subtracting the bond energies of the products.

First, you need to identify the bonds present in the reactants and products. In this case, the reactants are n₂(g) and 2 h₂(g) and the product is n₂h₄(g). Using the table of bond energies provided, you can find the bond energies for the N-N bond, H-H bond, and N-H bond. Summing up the bond energies of the reactants and subtracting the bond energies of the products will give you the enthalpy change (∆Hrxn) for the reaction.

Remember that the bond energies are for one mole of each bond, so you may need to multiply the bond energies by the coefficients in the balanced equation to account for the number of moles involved in the reaction.

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