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Calculate grxn at 339 k under the conditions shown below for the following reaction. report your value in kj. x2o3 (s) 3 yo (g) 2 x (s) 3 yo2 (g) = -25.6 kj pyo =0.6 atm, pyo2 = 2.2 atm

User Twg
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Final answer:

To calculate Gibbs free energy change of reaction (Grxn) at 339 K, we use the equation Grxn = Grxn^{°} + RT × ln(Q), where Q is (PYO2)3 / (PYO)3. We substitute the provided values to get Grxn in J, which is then converted to kJ.

Step-by-step explanation:

To calculate the Gibbs free energy change of reaction (Grxn) for the reaction X2O3 (s) + 3 YO (g) → 2 X (s) + 3 YO2 (g) at 339 K with given partial pressures for YO and YO2 gases, we can use the following equation:

Grxn = Grxn^{°} + RT × λln(Q)
Where Grxn^{°} is the standard free energy change of the reaction, R is the universal gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin, and Q is the reaction quotient. In this case, Q can be calculated as (PYO2)3 / (PYO)3.

Plugging the pressures into Q gives us Q = (2.2)3 / (0.6)3. The value of Grxn^{°} is given as -25.6 kJ. Converting kJ to J and substituting the values into the equation yields:

Grxn = (-25600 J) + (8.314 J/(mol·K))(339 K)ln(2.23 / 0.63)

Calculating this will give us the Grxn at 339 K in Joules, which can then be converted back to kilojoules.

User Perseverance
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