Question

Calculate the amount of heat energy released as the temperature is decreased for 58 grams of a metal, that has a specific heat constant cs of 0.53 kj/g*c. the temperature begins at 100c and is decreased to a final temperature of 25c.

Answer 1

The amount of heat energy released as the temperature is decreased for 58 grams of the metal is 2262.45 kJ.

Step-by-step explanation:

The amount of heat energy released as the temperature decreases can be calculated using the formula: q = mcsΔT, where q is the heat energy, m is the mass in grams, cs is the specific heat constant, and ΔT is the change in temperature.

In this case, the mass is 58 grams, the specific heat constant is 0.53 kJ/g°C, and the change in temperature is 100°C - 25°C = 75°C.

Substituting these values into the formula, we get: q = 58g × 0.53 kJ/g°C × 75°C = 2262.45 kJ.

Therefore, the amount of heat energy released as the temperature is decreased for 58 grams of the metal is 2262.45 kJ.