Question

Bowling balls are roughly the same size but come in a variety of weights. given that the official radius of a bowling ball should have is roughly 0.109 m, calculate the weight of the heaviest bowling ball that will float in a fluid of density 1x10^3

Answer 1

To calculate the weight of the heaviest bowling ball that will float in a fluid, we need to determine the maximum volume of fluid it can displace and then calculate the weight of that amount of fluid.

Step-by-step explanation:

The weight of an object that floats in a fluid is equal to the weight of the fluid displaced by the object. In order to calculate the weight of the heaviest bowling ball that will float in a fluid of density 1x10^3, we need to determine the maximum volume of fluid it can displace and then calculate the weight of that amount of fluid.

The volume of a sphere can be calculated using the formula V = (4/3)πR³, where R is the radius of the sphere. Substituting the given radius of 0.109 m, we can calculate the volume of the bowling ball. Then, we can determine the weight of the fluid it displaces by multiplying the volume by the density. Finally, we need to solve the equation W = m * g to find the weight of the heaviest bowling ball that will float in the fluid, where W is the weight, m is the mass, and g is the acceleration due to gravity.