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Based on the sample of 15 individuals above, what is the probability that a randomly selected individual will have alleles 3 and 8 at d3s1358 and alleles 4 and 6 at d8s1179? write your answer to the 5th decimal.

User Bulkan
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Final answer:

The probability of a randomly selected individual having a given set of alleles at two independent loci is calculated using the product rule, by multiplying the individual probabilities of each allele. Specific allele frequencies are needed to provide a precise answer.

Step-by-step explanation:

The question is concerned with calculating the probability of an individual possessing particular allelic combinations at two different loci, d3s1358 and d8s1179. Although specific frequencies are not given for these alleles, we can utilize general principles from Mendelian genetics and probability to answer similar questions. When dealing with two independent loci, the product rule can be applied, which states that the probability of two independent events both happening is the product of their individual probabilities.

For a hypothetical scenario, if allele 3 at d3s1358 occurs with a probability of p and allele 8 with a probability of q, and at d8s1179, allele 4 occurs with a probability of r and allele 6 with a probability of s, then the probability of an individual having all four alleles (3 and 8 at d3s1358, and 4 and 6 at d8s1179) is p * q * r * s. However, the specific frequencies for each allele would be needed to provide a numerical answer. In general, if the alleles are evenly distributed, the probability could be calculated as 1/number of alleles at each locus squared for each locus, assuming complete random segregation of gametes without any linkage.

User Parag Kadam
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