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At what temperature is a gas if 0.0851 mol of it is contained in a 604 dm3 vessel at 100.4 kpa?

User Radicate
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Final answer:

The temperature of the gas can be calculated by using the ideal gas law, PV = nRT, with the given values of pressure, volume, and the number of moles of the gas. By rearranging the formula to solve for temperature, and using R = 8.314 kPa·L/(mol·K), the temperature in Kelvin can be determined.

Step-by-step explanation:

To calculate the temperature of a gas under given conditions, we can use the ideal gas law, which is PV = nRT. Here, P stands for pressure, V for volume, n for the number of moles, R for the ideal gas constant, and T for temperature.

In this problem, we have the following variables: P = 100.4 kPa, V = 604 dm³, and n = 0.0851 mol. The ideal gas constant R when the pressure is in kPa is approximately 8.314 kPa·L/(mol·K).

To find the temperature T, we rearrange the ideal gas equation to T = PV/(nR). Substituting the values into the equation we get: T = (100.4 kPa × 604 dm³) / (0.0851 mol × 8.314 kPa·L/(mol·K)).

After performing the calculations, we determine the temperature in Kelvin which can then be easily converted to Celsius if needed by using the relation ΔT°C = T(K) - 273.15

User Snowy
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