Question

Write an equation of the line that passes through the pair of points (54, 1) and (−14, 34). a) y = - 33/34 x + 2081/34 b) y = - 33/40 x + 2081/40 c) y = -33/34 x + 2031/34 d) y = - 33/34 x + 2031/40

Answer 1

To find the equation of the line passing through the points (54, 1) and (-14, 34), we can use the slope-intercept form of a linear equation, y = mx + b. The slope between the two points is -33/34, and by substituting one of the points into the equation, we can solve for the y-intercept, which is 2081/34.

Step-by-step explanation:

To find the equation of the line that passes through the points (54, 1) and (-14, 34), we can use the slope-intercept form of a linear equation, y = mx + b, where m is the slope and b is the y-intercept.

First, we need to find the slope. The formula for slope is (y2 - y1)/(x2 - x1). So, the slope is (34 - 1)/(-14 - 54) = 33/(-68) = -33/34.

Next, we can choose one of the given points to substitute into the equation. Let's use the point (54, 1). We have y = -33/34 * x + b, substitute x = 54 and y = 1, then solve for b: 1 = -33/34 * 54 + b, b = 2081/34.

So, the equation of the line is y = -33/34 * x + 2081/34.