Final answer:
The axis of symmetry of the parabola y = x^2 + 3x - 1 is x = -3/2.
Step-by-step explanation:
The equation given is y = x^2 + 3x - 1. To find the axis of symmetry of the parabola represented by this equation, we need to use the formula x = -b/2a, where a and b are the coefficients of the quadratic equation in the form ax^2 + bx + c = 0.
In this case, a = 1, b = 3. Substituting these values into the formula, x = -3/(2*1) = -3/2. Therefore, the axis of symmetry of the parabola is x = -3/2 (option d).