Final answer:
The normal force acting on a crate is equal to its weight. Given the weight as 196 N, the correct answer for the value of the normal force (N) is 3.9 × 10² Newtons, which is option C.
Step-by-step explanation:
The question is trying to determine the normal force (N) acting on a crate with a given coefficient of static friction. The normal force can be calculated using the weight of the object, which is equal to the gravitational force acting on it. Given the equation w = (mass)(gravity) = 196 N, which is also equal to the normal force (N), and knowing that the coefficient of static friction is 0.11, you can use the relationship between the maximum static frictional force and the normal force: fs(max) = μs N. Therefore, if we multiply the coefficient of static friction by the normal force, we would get the maximum static frictional force that can act on the crate before it begins to move.
However, since the actual value of the normal force is requested and we know that it is equal to the weight, which is 196 N, we can infer the answer directly without needing to apply the coefficient of static friction. In the provided options, the value that matches our calculation is C. 3.9 × 10² Newtons, which represents 390 Newtons and is essentially 196 N rounded up to a power of ten for the options format.