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Start by identifying the temperatures on each thermometer.

Daleville: 5 4 3 2 1 0 -1 -2 -3 -4 -5 The temperature in Daleville is __ degrees Celsius.
a) 5
b) -5
c) 0
d) 10

Richmond: 5 4 3 2 1 0 -1 -2 -3 -4 -5 The temperature in Richmond is __ degrees Celsius.
a) 5
b) -5
c) 0
d) 10

User Sgonzalez
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1 Answer

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Final answer:

The temperatures in Daleville and Richmond are both inferred to be 5 degrees Celsius, assuming top to bottom reading without negatives. Converting a 40.0°F decrease to Celsius results in a 22.2°C decrease. Fahrenheit and Celsius scales intersect at -40 degrees, while Fahrenheit and Kelvin do not intersect.

Step-by-step explanation:

Regarding the temperatures provided for Daleville and Richmond, if the temperatures shown are in sequence from top to bottom, without the exact thermometer images or a description of where the markers fall, it's impossible to ascertain the exact temperature. However, if we assume that the sequence provided should be read from top to bottom, indicating descending temperatures with the top being the warmest, we would infer that Daleville's temperature is 5 degrees Celsius (Choice a) and Richmond is also 5 degrees Celsius (Choice a). These are the top numbers in the sequence provided, assuming no negative values are involved.

Furthermore, the relationship between temperature scales can be explored through examples and conversions. For instance, converting the temperature difference of 40.0°F to Celsius would involve using the conversion formula (40.0°F - 32) × (5/9), since the difference in scale between Fahrenheit and Celsius is that zero degrees Celsius is equivalent to thirty-two degrees Fahrenheit, and the size of the Celsius degree is 5/9 that of the Fahrenheit. This yields a temperature decrease of 22.2°C.

To find the temperature at which Fahrenheit and Celsius scales are the same, we set up the equations F = C and plug into the conversion formula (F - 32) × (5/9) = C, solving for F, which is approximately -40 degrees. The temperature at which Fahrenheit and Kelvin's scales are the same does not exist, as these scales do not intersect at any point because Kelvin starts at absolute zero, which is -273.15°C or -459.67°F, and increases by the same degree increments as the Celsius scale.

User Artagnon
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