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Find the total resistance in a series circuit with three resistances of 1092, 2002, and 3092

Ο Α. 60Ω
Ο Β. 1Ω
Ο C. 201
Ο D. 15Ω
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User Ed Pavlov
by
7.5k points

1 Answer

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The total resistance in the series circuit with three resistances of 10 Ω, 20 Ω, and 30Ω, is 60 Ω (option A)

How to calculate the total resistance of the circuit?

The total resistance of a circuit in series connection is written according the following formula:

R = R₁ + R₂ + R₃ +...+ Rₙ

Where

  • R is the total resistance
  • R₁ is the first resistance
  • R₂ is the second resistance
  • R₂ is the third resistance
  • Rₙ could be a fourth, fifth or sixth resistance

Now, we have three resistance in the circuit. Thus, we can calculate the total resistance in the circuit as follow:

  • Resistor 1 (R₁) = 10 Ω
  • Resistor 2 (R₂) = 20 Ω
  • Resistor 3 (R₃) = 30 Ω
  • Total resistance (R) = ?

R = R₁ + R₂ + R₃

R = 10 + 20 + 30

R = 60 Ω

Therefore, the current answer is option A

Complete question:

Find the total resistance in a series circuit with three resistances of 10 Ω, 20 Ω, and 30 Ω

Ο Α. 60Ω

Ο Β. 1Ω

Ο C. 201

Ο D. 15Ω

User Neeraj Tangariya
by
7.8k points