Question

Me left 0:chidren between the ages of 2 and 5 watch an average of 25 hours of tv per week. assume the variable is normally distributed with standard deviation of 2 hours. ifa child of age between 2 and 5 is randomly selected. what is the probability that the child is watching tv more than 26 hours per week. select one:

a.0.1915
b. not mentioned
c.0.3085
d. 0.8387 l

Answer 1

To find the probability that a child between the ages of 2 and 5 watches more than 26 hours of TV per week, we need to use the standard normal distribution. First, calculate the z-score using the formula z = (x - μ) / σ. Look up the probability corresponding to the z-score in the z-table.

Step-by-step explanation:

To find the probability that a child between the ages of 2 and 5 watches more than 26 hours of TV per week, we need to use the standard normal distribution.

First, we need to calculate the z-score of 26 hours using the formula z = (x - μ) / σ, where x = 26, μ = 25, and σ = 2.

Plugging in the values, we get z = (26 - 25) / 2 = 0.5. Next, we look up the probability corresponding to this z-score in the z-table.

The probability is the area under the curve to the right of the z-score. In this case, the probability is approximately 0.3085 (or 30.85%). Therefore, the correct answer is option c. 0.3085.